An electron moving at4.00 * 103m/sin a 1.25-Tmagnetic field experiences a magnetic force of1.40 * 10-16N. What angle does the velocity of theelectron make with the magnetic field? There are twoanswers

velocity of electron V = 4 x 10³ m/s

magnetic field B = 1.25 T.

magnetic force = 1.4 x 10⁻¹⁶ N.

If direction of velocity makes angle θ with magnetic field

magnetic force = magnetic field x charge on electron x velocity x sinθ

1.4 x 10⁻¹⁶ = 1.25 x 1.6 x 10⁻¹⁹ x 4 x 10³ x sinθ

1.4 x 10⁻¹⁶ = 8 x 10⁻¹⁶ x sinθ

sinθ = 1.4 / 8

=.175

θ = 10 degree

or 180 - 10

= 170 degree

because

sinθ = sin (180 - θ)