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24 July, 13:54

The hydrogen atom consists of a proton of mass 1.67x10-27 kg and an orbiting electron of mass 9.11x10-31 kg. In one of its orbits, the electron is 5.3x10-11 m from the proton. What is the mutual attractive gravitational force between the electron and the proton?

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  1. 24 July, 14:07
    0
    The mass of the proton,

    m

    p

    =

    9.11

    *

    10

    -

    31

    k

    g

    The mass of the electron,

    m

    e

    =

    1.67

    *

    10

    -

    27

    k

    g

    The distance between them,

    r

    =

    5.3

    *

    10

    -

    11

    m

    The gravitational force between two objects of mass,

    m

    1

    , and

    m

    2

    , separated by a distance,

    r

    , is given by the following equation:

    F

    =

    G

    m

    1

    m

    2

    r

    2

    Here,

    G

    =

    6.67

    *

    10

    -

    11

    m

    3

    /

    k

    g

    .

    s

    2

    is the gravitational constant.

    On plugging the given values, we have:

    F

    =

    6.67

    *

    10

    -

    11

    *

    1.67

    *

    10

    -

    27

    *

    9.11

    *

    10

    -

    31

    (

    5.3

    *

    10

    -

    11

    )

    2

    =

    3.61

    *

    10

    -

    47

    N
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