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20 May, 14:17

5. Two negative charges that are both - 3.8 C push each other apart with a force of 19.0 N. How far apart

are the two charges?

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Answers (1)
  1. 20 May, 14:32
    0
    82700 m

    Explanation:

    Applying Coulomb's law of electrostatic

    F = kq²/r² ... Equation 1

    Note: Both charges are the same

    Where F = force of attraction, q = negative charge, r = distance between the charges, k = coulomb's constant

    make r the subject of the equation

    r = √ (kq²/F) ... Equation 1

    Given: F = 19 N, q = 3.8 C, k = 9*10⁹ Nm²/C²

    Substitute these values into equation 2

    r = √ (3.8²*9*10⁹/19)

    r = √ (68.4*10⁸)

    r = 8.27*10⁴ m

    r = 82700 m

    Hence the two charges are 82700 m apart
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