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1 May, 06:57

The heat transfer coefficient for hydrogen flowing over a sphere is to be determined by observing the temperature-time history of a sphere fabricated from pure copper. The sphere, which is 20.0 mm in diameter, is at 70°C before it is inserted into the gas stream having a temperature of 27°C. A thermocouple on the outer surface of the sphere indicates 50°C 97 s after the sphere is inserted into the hydrogen. Find

a) What is the value of the specific heat of the copper at the average temperature of the process, in J/kg·K?

b) What is the value of the lumped thermal capacitance of the sphere, in J/K?

c) Solve for the thermal time constant, in sec.

d) What is the value of the heat transfer coefficient, in W/m2· K?

e) What is the value of the Biot number?

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Answers (1)
  1. 1 May, 07:14
    0
    h = 74.7177 W/m^2 K

    Explanation:

    Given:-

    - The diameter of the sphere, Ds = 20.0 mm

    - The initial Temperature of sphere, Ti = 70°C

    - The temperature of gas stream, Ts = 27°C

    - The thermocouple reading after 97s, Tr = 50°C

    Solution:-

    - We will use Table A-1, to extract the following properties of copper at Ti = 70°C (343 K):

    Density ρ = 8933 kg/m^3

    Specific Heat capacity cp = 389 J / kg. K

    Thermal conductivity, k = 388 W/m. K

    - The time-temperature history is given by the equations:

    θ (t) / θi = exp ( - t / Rt*Ct)

    Where,

    Rt = 1 / h*As, Ct = ρ*V*cp, As = πDs^2 / 4, θ = T - T∞

    V = πDs^3 / 6.

    - We will use the above relationships and given data to calculate:

    θ (t) = T (at 97s) - T∞ = Tr - Ts

    = 50 - 27 = 23°C

    θi = Ti - T∞ = Ti - Ts

    = 70 - 27 = 43°C

    - Then we have:

    θ (t) / θi = 23 / 43 = 0.53488372

    θ (t) / θi = exp ( - t / τ)

    0.53488372 = exp ( - t / τ)

    Solve for τ:

    τ = - 97 / Ln (0.53488372)

    τ = 155.025 s

    - Then solve for h:

    τ = ρ*V*cp / h*As

    h = ρ*V*cp / τ*As

    h = (8933) * (0.02/6) * (389) / (155.025)

    h = 74.7177 W/m^2 K

    - Verifying the use of spatial isothermal assumption:

    Lc = Ds / 6 = 20 / 6 = 0.003333

    Bi = h*Lc / k = (74.7177) * (0.00333) / 388 = 0.00064

    Hence, Bi < 0.1 so, spatial isothermal assumption is valid.
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