g Over a time interval of 2.28 years, the velocity of a planet orbiting a distant star reverses direction, changing from + 22.4 km/s to - 17.5 km/s. Find (a) the total change in the planet's velocity (in m/s) and (b) its average acceleration (in m/s2) during this interval. Include the correct algebraic sign with your answers to convey the directions of the velocity and the acceleration.

Question

Janiyah Grimes

Physics

9 May, 06:04

g Over a time interval of 2.28 years, the velocity of a planet orbiting a distant star reverses direction, changing from + 22.4 km/s to - 17.5 km/s. Find (a) the total change in the planet's velocity (in m/s) and (b) its average acceleration (in m/s2) during this interval. Include the correct algebraic sign with your answers to convey the directions of the velocity and the acceleration.

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Answers (1)

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Alejandro Christensen · Answer 1

(A) ΔV = - 39900m/s

(B) a = - 5.55 * 10-⁴ m/s²

Explanation:

ΔV = V2 - V1 = - 17.5 - 22.4 = - 39.9km/s = - 39.9 * 1000m/s

= - 39900m/s

Δt = 2.28years = 2.28 * 365.25days

= 2.28 * 365.25 * 86400s = 71951328s

a = ΔV/Δt = - 39900m/71951328s = - 5.55 * 10-⁴m/s²