Suppose the rocket is coming in for a vertical landing at the surface of the earth. The captain adjusts the engine thrust so that rocket slows down at the rate of 2.05 m/s2. A 6.50-kg instrument is hanging by a vertical wire inside a space ship. Find the force that the wire exerts on the instrument.

R = 78.32 N

Explanation:

Given that

Acceleration, a = 2.05 m/s²

Mass, m = 6.5 kg

The force due to acceleration

F = mass x Acceleration

F = ma

F = 6.5 x 2.05 N

F = 13.32 N

The force due to weight

F' = m g

F' = 6.5 x 10 N (take g = 10 m/s²)

F' = 65 N

Therefore the net total force will be summation of force due to weight and force due to acceleration

R = F + F'

R = 65 + 13.32 N

R = 78.32 N