A collie drags its bed box across a floor by applying a horizontal force of 6.5 N. The kinetic frictional force acting on the box has magnitude 1.8 N. As the box is dragged through 0.84 m along the way, what are (a) the work done by the collie's applied force and (b) the increase in thermal energy of the bed and floor?

Question

Isaiah Montgomery

Physics

11 March, 15:51

A collie drags its bed box across a floor by applying a horizontal force of 6.5 N. The kinetic frictional force acting on the box has magnitude 1.8 N. As the box is dragged through 0.84 m along the way, what are (a) the work done by the collie's applied force and (b) the increase in thermal energy of the bed and floor?

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Answers (1)

Know the Answer?

Lawson Walton · Answer 1

(a) 5.46 J

(b) 1.51 J

Explanation:

Work done=Force * Distance

(a)

Work done = Applied horizontal force * Distance

Substituting distance with 0.84m, Force by 6.5N

Work done=6.5*0.84=5.46 Nm or J

(b)

Increase in thermal energy of the bed and floor

The increase in energy is caused by frictional force whose value is provided as 1.8 N

Therefore, energy=Force*distance

Using distance of 0.84m and force of 1.8N

Energy=1.8*0.84=1.512 Nm or J