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3 May, 04:05

A solid metal sphere of radius a = 2.5 cm has a net charge Qin = - 3 nC (1 nC = 10-9C). The sphere is surrounded by a concentric conducting spherical shell of inner radius b = 6 cm and outer radius c = 9 cm. The shell has a net charge Qout = + 2 nC. What is V0, the electric potential at the center of the metal sphere, given the potential at infinity is zero? V0 =

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  1. 3 May, 04:31
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    Answer: 630 V

    Explanation: In order to solve this problem we have to consider the potential given by:

    In the region 0
    V (r) = - ∫E*dr where E can be calculated by Gaussian law then E = k*qa/r^2

    where qa=-3 nC

    then

    The V (r) = k*qa/r+C C is zero since V (r=∞) = 0

    Finally we have

    V (r) = k*qa (1/r) - (1/b)

    thus V (a) = k*qa (1/a) - (1/b)

    Replacing the values V (a) = 630 V, as the solid metal sphere is a equipotential object thus at the center have the same value of V that in r=a (630 V).
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