Ask Question
31 October, 07:27

Q3. A car is initially heading east at 55.0 km h when it turns a corner and heads N 55° Eat

65.0 km h - 1. Determine the change in the velocity of the car during this time.

+2
Answers (1)
  1. 31 October, 07:28
    0
    37.3 km/h at N 2.70° E

    Explanation:

    Find the horizontal and vertical components of the initial velocity (u) and final velocity (v). Remember that N 55° E means 55° east of north.

    uₓ = 55.0 km/h

    uᵧ = 0 km/h

    vₓ = 65.0 km/h * sin 55° = 53.24 km/h

    vᵧ = 65.0 km/h * cos 55° = 37.28 km/h

    Find the difference.

    vₓ - uₓ = - 1.76 km/h

    vᵧ - uᵧ = 37.28 km/h

    The magnitude is:

    |v - u| = √ ((-1.76 km/h) ² + (37.28 km/h) ²)

    |v - u| = 37.3 km/h

    The direction is:

    θ = tan⁻¹ (37.28 / - 1.76)

    θ = 92.70°

    θ = N 2.70° E
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Q3. A car is initially heading east at 55.0 km h when it turns a corner and heads N 55° Eat 65.0 km h - 1. Determine the change in the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers