A bug of mass 2.2 g is sitting at the edge of a cd of radius 3.0 cm. if the cd is spinning at 280 rpm, what is the angular momentum of the bug?

M = 2.2 g = 2.2 x 10⁻³ kg, the mass of the bug.

r = 3.0 cm = 0.03 m, the radial distance from the center.

The angular speed is

ω = 280 rpm

= (280 rev/min) * (2π rad/rev) * (1/60 min/s)

= 29.3215 rad/s

The moment of inertia of the bug is

I = mr²

= (2.2 x 10⁻³ kg) * (0.03 m) ²

= 1.98 x 10⁻⁶ kg-m²

Calculate the angular momentum of the bug.

J = Iω

= (1.98 x 10⁻⁶ kg-m²) * (29.3215 rad/s)

= 5.806 x 10⁻⁵ (kg-m²) / s

Answer: 5.806 x 10⁻⁵ (kg-m²) / s