A 6-inch diameter smooth plastic pipe 3100 ft in length delivers 2.2 cfs of water between two reservoirs. Water viscosity is 11.11 x 10-6 ft2/s. What is the elevation difference (ft) in water surface between the reservoirs

h = 6.39 m

Explanation:

radius = 6/2 = 3in = 3/12 in/ft = 0.25 ft

apply continuity equation to evaluate the velocity

flow rate = area * velocity

2.2 = π (0.25^2) * V

⇒ V = 11.2 ft/s

*assuming there is no applied pressure difference along the pipe

applying Energy conservation law

initial potential energy = final kinetic energy

pgh = (1/2) * pv^2

where p = density

v = velocity

plugging in the values:

p cancels out on both the sides

⇒ 9.81 * h = (11.2^2) / 2

h = 6.39 m