It takes about 6 sec for a stone dropped from rest at the top of a vertical mine shaft to hit the bottom of the shaft. how deep is the shaft?

The answer is about 180 m.

Using d = (1/2) g t2

= (1/2) (9.8) (36)

= about 180 m.

It takes about 6 sec for a stone dropped from rest at the top of a vertical mine shaft to hit the bottom of the shaft., the depth of the shaft is about 180m.