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18 June, 11:15

A 400 kg object is sitting at rest at the top of a hill that is 30.0m high and 80.0m long measured along the hill. If there is no friction, how fast will the object be going at the bottom of the hill?

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  1. 18 June, 11:30
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    Theater=sin^-1 (30/80)

    theater=22

    F=400gsin22=150N

    F=ma

    150=400a

    a=0.375ms^-2

    v^2-u^2=2as

    v^2-0=2x0.375x80

    v=7.75ms^-1
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