A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 594 N. As the elevator later stops, the scale reading is 396 N. Assume the magnitude of the acceleration is the same during starting and stopping.

Question

Yoselin Pope

Physics

1 January, 13:35

A person stands on a scale in an elevator. As the elevator starts, the scale has a constant reading of 594 N. As the elevator later stops, the scale reading is 396 N. Assume the magnitude of the acceleration is the same during starting and stopping.

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Answers (1)

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Kenyon Zhang · Answer 1

4.9 m/s²

Explanation:

F = reading of the elevator while running = 594 N

W = weight of person and elevator together when at stop = 396 N

m = mass of person and elevator together

a = acceleration of elevator

Weight of the person is given as

W = mg

inserting the values

396 = m (9.8)

m = 40.4 kg

Force equation for the motion of the elevator is given as

F - W = ma

Inserting the values

594 - 396 = (40.4) a

a = 4.9 m/s²