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an object accelarates from rest to a velocity of 2.4m/s over a distance of 16m what was its accelaration

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  1. 30 July, 09:00
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    Data given:

    Velocity:2.4m/s

    Displacement:16m

    Formula needed:

    v² = (v0) ²+2aΔx

    Solution:

    2,4²=0²+2a*10

    5,76=2a·10

    2a=5,76:10

    2a=0,576

    a=0,576:2

    a=0,288m/s²
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