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A 1.0 kg lump of clay is sliding to the right on a frictionless surface with speed 2 m/s. It collides head-on and sticks to a 0.5 kg metal sphere that is sliding to the left with speed 4 m/s. What is the kinetic energy of the combined objects after the collision?

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  1. 25 July, 11:39
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    0J

    Explanation:

    Mass of the lump M1 = 1.0 kg, initial velocity of the lump U1 = 2m/s to the right,

    mass of the metal sphere M2 = 0.5kg, initial velocity of the metal sphere M2 = - 4m/s to the left. using conservation law of momentum;

    M1U1 + M2U2 = V (M1 + M2)

    (1.0 * 2) + (0.5 * - 4) = V (1 + 0.5)

    2 - 2 = V (1.5)

    0 = V (1.5)

    divide both side by 1.5

    0/1.5 = V 1.5/1.5

    V = 0

    since final velocity after sticking together of the two masses equals zero then their combined kinetic energy will also equal to zero

    1/2 V (M1 + M2)

    1/2 * 0 * 1.5 = 0J
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