The floor of a rectangular deck has a length that is 6 feet more than it's width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?

A. x^2 + 12x + 27

B. x^2 + 9x + 18

C. x^2 + 9x

D. x^2 + 6x

Question

Kendrick Ibarra

Advanced Placement (AP)

1 October, 03:01

The floor of a rectangular deck has a length that is 6 feet more than it's width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?

A. x^2 + 12x + 27

B. x^2 + 9x + 18

C. x^2 + 9x

D. x^2 + 6x

+4

Answers (1)

Know the Answer?

Maximus Mclean · Answer 1

The correct Answer is A. x^2 + 12x + 27

Width of floor = w = x

Length of floor = l = x + 6

New dimesions are increase by three so our

W = x + 3

L = x + 6 + 3 = > L = x + 9

As we know that Area = width*length so

area = W * L

= (x + 3) * (x + 9)

= x∧2 + 9x + 3x + 27

= x∧2 + 12x + 27

Which is our option A.

The floor of a rectangular deck has a length that is 6 feet more than it's width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?A. x^2 + 12x + 27B. x^2 + 9x + 18C. x^2 + 9xD. x^2 + 6x

The floor of a rectangular deck has a length that is 6 feet more than it's width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?

A. x^2 + 12x + 27

B. x^2 + 9x + 18

C. x^2 + 9x

D. x^2 + 6x