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Advanced Placement (AP)
27 November, 19:21
If f (x) = (x^2-2x-1) ^2/3, then f' (0) is?
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Mcbride
27 November, 19:45
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F' (x) = (2/3 (x^2-2x-1) ^-1/3) * (2x-2) chain rule here
f' (0) is equals to substitute x with 0. Which gives
f' (0) = (2/3 (-1) ^-1/3) * (-2)
Plug in the calculator, and your answer is ready
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