A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recessive allele (h). Use the Hardy-Weinberg equation to determine the frequencies of the three genotypes:

p^2 + 2pq+q^2=1

f (HH) = p2 =

f (Hh) = 2pq =

f (hh) = q2 =

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2 July, 02:44

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Slade Maynard · Answer 1

Slade Maynard 2 July, 02:48

0

HH. 04

Hh. 16

hh -.64

i think

Lane Dunn · Answer 2

f (HH) = p 2 = 0.04

f (Hh) = 2pq = ⇒ 0.32,.32

f (hh) = q 2 = ⇒ 0.64,.64

A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recessive allele (h). Use the Hardy-Weinberg equation to determine the frequencies of the three genotypes:p^2 + 2pq+q^2=1f (HH) = p2 =f (Hh) = 2pq =f (hh) = q2 =