Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?

A. 72.25 percent

B. 2.25 percent

C. 12.75 percent

D. 25.5 percent

Question

Carelyn

Biology

Today, 01:47

Suppose a population is carrying a condition controlled by two alleles: R (dominant) and r (recessive). If the frequency of the r allele is 15%, and the frequency of the R allele is 85%, what will be the frequency of the RR genotype, assuming evolution is not occurring?

A. 72.25 percent

B. 2.25 percent

C. 12.75 percent

D. 25.5 percent

+4

Answers (2)

Know the Answer?

Emilee Johnston · Answer 1

A. Since the frequency of the R allele is 0.85, the frequency of the RR genotype would be 0.85^2 = 0.7225.

Amir · Answer 2

A. 72.25 percent

Explanation:

The frequency of a genotype is calculated by the product of multiplying allele frequencies.

The R allele has a frequency of 85% (0.85), so for a homozyguous individual RR:

f (R) * f (R) = 0.85 * 0.85 = 0.7725

0.7725 * 100 = 77.25%

It is concluded that the frequency for RR genotype is 77.25%.