Inside one osmosis bag*, A, is a 50% glucose solution and inside bag B is a 20% glucose solution. Both bags are put into beakers containing 100% water. What will happen to the bags?

A) Bag A will gain weight.

B) Bag B will gain weight.

C) Both bags will gain weight.

D) Both bags will lose weight.

E) Both bags will remain the same.

Question

Benny

Biology

9 July, 12:54

Inside one osmosis bag*, A, is a 50% glucose solution and inside bag B is a 20% glucose solution. Both bags are put into beakers containing 100% water. What will happen to the bags?

A) Bag A will gain weight.

B) Bag B will gain weight.

C) Both bags will gain weight.

D) Both bags will lose weight.

E) Both bags will remain the same.

+4

Answers (1)

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Bryson Thomas · Answer 1

Answer:C) Both bags will gain weight.

Explanation: osmosis is the movement of water molecules from a region of low concentration of solute to a region of high concentration of solute, through a semi permeable membrane.

It is one of the ways in which living cells move substances across it's membrane.

In the above case, the bags are semi-permeable and so can allow the movement of water molecules through it.

Both bags contains water with glucose dissolved in them, although bag A has a higher concentration of solute (glucose).

When placed in the 100% water, water would flow into both bags through osmosis. this will occur because the concentration of solute in the bags is higher than that outside the bags.

As a result both bags would gain weight due to entry of water.

However, Bag A which has more glucose in it, would gain more water.