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20 December, 02:39

In guinea pigs, long fur is dominant to short fur. If two heterozygous guinea pigs are mated, what is the probability that they will have (show your calculations for both questions):

a. three short hair babies in a row?

b. three long hair babies in a row?

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  1. 20 December, 02:41
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    Let the dominant long fur be represented by L and the recessive short fur be l. The parents are therefore:

    Ll x Ll

    This cross produces the following offspring:

    LL, Ll, Ll and ll

    From the above cross, we can see that there is a 3/4 chance of an offspring with long fur and a 1/4 chance of an offspring with short fur. Now, calculating:

    a) Three short fur babies means the event has to happen in successions thrice, which implies multiplication in probability. This is:

    P (3 short fur) = 1/4 * 1/4 * 1/4

    P (3 short fur) = 1/64

    b) the same method is used for babies with long fur:

    P (3 long fur) = 3/4 * 3/4 * 3/4

    P (3 long fur) = 27/64
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