How many electrons are transferred in the iconic bond between sodium and chorine in NaCI

Answer: One electron

Explanation:

Sodium Na, has atomic number of 11, and a configuration of 2, 8, 1

Chlorine Cl, has atomic number of 17, and a configuration of 2, 8, 7

Thus, to form an ionic bond Sodium transfer its one outermost electron to chlorine.

Hence Sodium becomes Na + (2,8) while Chlorine becomes Cl - (2, 8, 8) in NaCl and both have stable octet structure.