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18 December, 11:07

You have a population in hardy-weinberg equilibrium for the m and n alleles. these alleles are codominant. the allele frequency of m is 0.4. what is the frequency of heterozygotes in the population

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  1. 18 December, 11:14
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    Answer: 48%

    Because the population is in hardy-weinberg equilibrium, that means the sum of m and n alleles frequency would be 1

    If m is 0.4, then n would be:

    m+n=1

    0.4+n=1

    n=0.6

    The frequency of organism with heterozygote genotype would be:

    2 * m * n = 2 * 0.4 * 0.6=0.48=48%
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