Consider a locus with two alleles, A and a. If the rate of mutation of A to a is 0.0000025 and the rate of mutation of a to A is 0.0000010, what will be the equilibrium frequency of the A allele? (Recall that the equilibrium allele frequency under mutation is p * = v / (m + v), where p * is the equilibrium frequency of the A allele, m is the rate of mutation from A to a, and v is the rate of mutation from a to A.)

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21 July, 19:27

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Jesse Jordan · Answer 1

The equilibrium frequency is:

p * = v / (m + v)

p * = 0.0000010 / (0.0000025 + 0.0000010) : 0.2857142857