Wolves are sometimes observed to have black coats and blue eyes. Assume that these traits are controlled by single locus genes and are located on different chromosomes. Assume further that normal coat color (N) is dominant to black (n) and brown eyes (B) are dominant to blue (b). Suppose the alpha male and alpha female of a pack are black with blue eyes (alpha male) and normal colored with brown eyes (alpha female), respectively. The female is heterozygous for both traits and male is homozygous for both traits. What would be the genotypic and phenotypic ratio of their offspring? (show punnet)

Question

Dominique Kelly

Biology

18 December, 21:40

Wolves are sometimes observed to have black coats and blue eyes. Assume that these traits are controlled by single locus genes and are located on different chromosomes. Assume further that normal coat color (N) is dominant to black (n) and brown eyes (B) are dominant to blue (b). Suppose the alpha male and alpha female of a pack are black with blue eyes (alpha male) and normal colored with brown eyes (alpha female), respectively. The female is heterozygous for both traits and male is homozygous for both traits. What would be the genotypic and phenotypic ratio of their offspring? (show punnet)

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Pineda · Answer 1

The answer is

genotypic ratio: 1 : 1 : 1 : 1

phenotypic ratio: 1 : 1 : 1 : 1

Alpha male phenotype: homozygous black fur and homozygous blue eyes

Alpha male genotype: nnbb

Alpha female phenotype: heterozygous normal fur and heterozygous brown eyes

Alpha female genotype: N nBb

According to the Punnet square, their offspring will have the following ratios:

genotypic ratio - 1 : 1 : 1 : 1 (NnBb, Nnbb nnBb nnbb)

phenotypic ratio - 1 : 1 : 1 : 1 (normal fur and brown eyes (NnBb), normal fur and blue eyes (Nnbb), black fur and brown eyes (nnBb), and black fur and blue eyes (nnbb))