Ask Question
18 May, 06:42

Which population is most likely to be in Hardy-Weinberg equilibrium?

A=a large population of ocean fish that lives in an unpolluted ecosystem that has abundant food

B=a large population of prairie grasses that lives in an ecosystem that is frequently burned by wild fires

C=a medium-sized population of birds that lives on a chain of islands that have different food sources

D=a medium-sized population of bacteria that lives on crop plants that are frequently sprayed with pesticides

+2
Answers (2)
  1. 18 May, 06:53
    0
    The correct answer is letter A. This population would be a part of the Hardy-Weinberg equilibrium: a large population of ocean fish that lives in an unpolluted ecosystem that has abundant food. This principle states that alleles and genotype frequencies will remain constant through many generations because of the absence of evolutionary influences.
  2. 18 May, 06:54
    0
    The correct answer is letter (B) a large population of prairie grasses that lives in an ecosystem that is frequently burned by wild fires. The Hardy-Weinberg principle is known as the Hardy-Weinberg model, theorem, equilibrium or law that says the genotype and allele frequenceis in a population will be constant given that there will be no other evolutionary influences.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Which population is most likely to be in Hardy-Weinberg equilibrium? A=a large population of ocean fish that lives in an unpolluted ...” in 📗 Biology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers