A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

Question

Devan Lawson

Biology

8 December, 23:14

A 7 L sample of gas has a pressure of 1.1 atm at a temperature of 285 K. If the pressure decreases to 0.6 atm, causing the volume to increase to 10 L, what is the new temperature? Round your answer to the nearest tenth.

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Answers (1)

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Jaidyn Kirby · Answer 1

The answer is 314.6 K

Gay-Lussac’s law:

PV = kT

P - pressure

V - volume

T - temperature

k - constant

k = PV/T = P1 * V1 / T1 = P2 * V2 / T2 = ...

P1 * V1 / T1 = P2 * V2 / T2

P1 = 1.1 atm

V1 = 7 L

T1 = 285 K

P2 = 1.1 atm - 0.6 atm = 0.5 atm

V2 = 7 L + 10 L = 17 L

T2 = ?

1.1 * 7 / 285 = 0.5 * 17 / T2

7.7 / 285 = 8.5 / T2

T2 = 8.5 * 285 / 7.7

T2 = 314.6 K