Which of the following summarizes expression of the lac genes in this partical diploid: I + P + Oc Z - Y + / I - P + O + Z + Y-? Which of the following summarizes expression of the lac genes in this partical diploid: I + P + Oc Z - Y + / I - P + O + Z + Y-? Beta-galactosidase is made both in the presence of and in the absence of lactose; permease is only made when lactose is present. Both permease and beta-galactosidase are made both in the presence of and in the absence of lactose. Both permease and beta-galactosidase are made only when lactose is present. Permease is made both in the presence of and in the absence of lactose; beta-galactosidase is only made when lactose is present.

Question

Eileen

Biology

30 August, 09:00

Which of the following summarizes expression of the lac genes in this partical diploid: I + P + Oc Z - Y + / I - P + O + Z + Y-? Which of the following summarizes expression of the lac genes in this partical diploid: I + P + Oc Z - Y + / I - P + O + Z + Y-? Beta-galactosidase is made both in the presence of and in the absence of lactose; permease is only made when lactose is present. Both permease and beta-galactosidase are made both in the presence of and in the absence of lactose. Both permease and beta-galactosidase are made only when lactose is present. Permease is made both in the presence of and in the absence of lactose; beta-galactosidase is only made when lactose is present.

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Answers (1)

Know the Answer?

Amaris Chaney · Answer 1

Option (4).

Explanation:

Lac operon is present in E. coli that regulate the metabolism of lactose in the bacteria. Lac Operon consists of three genes : Lac Y, lac Z and lac A, an operator and a promoter.

I + P + Oc Z - Y + / I - P + O + Z + Y-, in this case inducer is present, promoter is present, constitutive region and the gene lac Z and lac Y indicates the Z and Y. The permease enzyme will made in the presence and absence of lactose due to the presence of I + P + Oc in the cell but beta galactosidase is only made in presence of lactose as Y - gene is present in the diploid cell.

Thus, the correct answer is option 4.