Suppose you perform a monohybrid cross of two pea plants. the plants are heterozygous at the locus for stem height. t is dominant to t. t confers tall plant height. when you count the progeny, you find that there are 188 tall plants and 62 short plants. does this approximate the 3:1 phenotypic ratio caused by mendelian inheritance?

a. no, you would expect there to be more short plants.

b. yes, there are approximately 3 short plants for every tall plant.

c. no, the number of each phenotype is not in the exact ratio of 3:1.

d. yes, there are approximately 3 tall plants for every short plant. submit for grading save and finish later

Question

Sanai Aguilar

Biology

6 September, 22:54

Suppose you perform a monohybrid cross of two pea plants. the plants are heterozygous at the locus for stem height. t is dominant to t. t confers tall plant height. when you count the progeny, you find that there are 188 tall plants and 62 short plants. does this approximate the 3:1 phenotypic ratio caused by mendelian inheritance?

a. no, you would expect there to be more short plants.

b. yes, there are approximately 3 short plants for every tall plant.

c. no, the number of each phenotype is not in the exact ratio of 3:1.

d. yes, there are approximately 3 tall plants for every short plant. submit for grading save and finish later

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Answers (1)

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Triston Davidson · Answer 1

If T is the dominant allele and expresses the tall phenotype and t is recessive allele for short plants.

The parents are heterozygous Tt

cross between parents

Tt x Tt

offspring TT Tt tT tt

tall plants - TT, Tt and tT - 75%

short plants - tt - 25%

ratio of tall plants to short plants - 0.75 : 0.25

0.75/0.25 = 3

In the cross performed, 188 tall : 62 short

188/62 = 3.03

the obtained results follow the 3:1 phenotypic ratio approximately.

answer is b. yes, there are approximately 3 short plants for every tall plant.