Ask Question
6 September, 22:54

Suppose you perform a monohybrid cross of two pea plants. the plants are heterozygous at the locus for stem height. t is dominant to t. t confers tall plant height. when you count the progeny, you find that there are 188 tall plants and 62 short plants. does this approximate the 3:1 phenotypic ratio caused by mendelian inheritance?

a. no, you would expect there to be more short plants.

b. yes, there are approximately 3 short plants for every tall plant.

c. no, the number of each phenotype is not in the exact ratio of 3:1.

d. yes, there are approximately 3 tall plants for every short plant. submit for grading save and finish later

+4
Answers (1)
  1. 6 September, 23:10
    0
    If T is the dominant allele and expresses the tall phenotype and t is recessive allele for short plants.

    The parents are heterozygous Tt

    cross between parents

    Tt x Tt

    offspring TT Tt tT tt

    tall plants - TT, Tt and tT - 75%

    short plants - tt - 25%

    ratio of tall plants to short plants - 0.75 : 0.25

    0.75/0.25 = 3

    In the cross performed, 188 tall : 62 short

    188/62 = 3.03

    the obtained results follow the 3:1 phenotypic ratio approximately.

    answer is b. yes, there are approximately 3 short plants for every tall plant.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Suppose you perform a monohybrid cross of two pea plants. the plants are heterozygous at the locus for stem height. t is dominant to t. t ...” in 📗 Biology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers