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24 April, 16:42

The order of genes on a plant chromosome is A, B, and D, where A and B have a recombination frequency of 0.2, and B and D have a recombination frequency of 0.3. A pure-breeding plant that has the dominant A and B phenotypes with a recessive d phenotype is crossed to a pure-breeding plant that has the recessive a and b phenotypes with the dominant D phenotype. The resulting hybrid is crossed to a plant that has all three recessive phenotypes. Under the assumption that interference in this region is zero, what percentage of each progeny type would result from a single crossover between A and B

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  1. 24 April, 16:45
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    Answer: 12% Abd/abd 12%aBD/abd

    Explanation: When recombination frequency (RF) between A and B is given as 0.2

    Recombination frequency between B and D = 0.3

    Where double crossover frequency (DCO) is calculated as 0.2 * 0.3 = 0.06

    The interference assumed as = 0

    Single crossover (SCO) can be calculated as recombination frequency of (B and D) - Double crossover frequency which is 0.3 - 0.06 = 0.24

    Each recombinant event has an overall result of two (2) types

    Therefore; 24:2 = 12%

    = 12% Abd/abd and 12%aBD/abd
  2. 24 April, 17:05
    0
    It is given that RF (recombination frequency) between A and B = 0.2

    RF between B and D = 0.3

    Now, DCO (Double Crossover frequency) can be calculated as 0.2 X 0.3 = 0.06

    Interference assumed = 0

    We can now calculate for SCO as RF (B and D) - DCO frequency

    = 0.3 - 0.06 = 0.24

    Since, the result of each recombinant event is two recombinant types, hence,

    24/2 = 12% Abd/abd and 12%aBD/abd
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