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8 August, 11:21

A blue-eyed, left-handed woman marries a brown-eyed, right-handed man who is heterozygous for both of his traits. if blue eyes and left-handedness are recessive, how many different phenotypes are possible in their children?

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  1. 8 August, 11:42
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    4 different phenotypes may be produced. If you write this down in a Punnet square you can get the exact ratio and the genotypes along with the phenotypes.

    Let us assign B for brown eyes, b for blue eyes; H for right-handed, h for left-handed.

    The mother's genotype will then be bbhh

    The father's genotype will then be BbHh

    bh bh bh bh

    BH BbHh BbHh BbHh BbHh

    Bh Bbhh Bbhh Bbhh Bbhh

    bH bbHh bbHh bbHh bbHh

    bh bbhh bbhh bbhh bbhh

    Now based on that you can see that there are 4 possible genotypic combinations which would express different phenotypic combinations as well.

    BbHh: Brown-eyed, right-handed

    Bbhh: Brown-eyed, left-handed

    bbHh: Blue-eyed, right handed

    bbhh: Blue-eyed, left-handed

    So again, there would be 4 possible phenotypes.
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