In maize (corn), assume that the genes A and B are linked and 30 map units apart. If a plant of Ab/aB is selfed, what proportion of the progeny would be expected to be of ab/ab genotype? A) 2.25% B) 15% C) 9%D) 30%E) 4.5%

Question

Guest

Biology

9 August, 06:19

In maize (corn), assume that the genes A and B are linked and 30 map units apart. If a plant of Ab/aB is selfed, what proportion of the progeny would be expected to be of ab/ab genotype? A) 2.25% B) 15% C) 9%D) 30%E) 4.5%

+1

Answers (1)

Know the Answer?

Avah Lindsey · Answer 1

2.25%.

Explanation:

The recombination progeny occur due to the crossing over of the homologous chromosomes. The linked gene is 30 map units apart and the recombination frequency is 30.

If a plant of Ab/aB is selfed then the progeny obtained is as follows: Ab - parental - 35%, aB - parental - 35%, AB - recombinant - 15% and ab - recombinant - 15%. The cross between the F2 progeny with aabb is (0.15 * 0.15) = 0.0225 or 2.25%.

Thus, the answer is option (A).