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25 September, 03:28

Gene A converts compound A (red) to compound B (blue). Gene B converts compound B to compound C (green). These compounds determine the color of the individual. In a cross between a double heterozygote and an all recessive individual, what proportion of red to green offspring should be seen/1. 1:3

2. 3:1

3. 3:4

4. 4:3

5. 4:9

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  1. 25 September, 03:37
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    1:2 (red: green)

    Explanation:

    Given that:

    Gene A converts compound A (red) to compound B (blue); &

    Gene B converts compound B to compound C (green).

    If a cross between a double heterozygous and recessive individual occurs

    i. e AaBb * aabb

    what proportion of red to green offspring should be seen?

    So, we have the gametes of AaBb = (AB, Ab, aB, ab)

    aabb = (ab, ab, ab, ab)

    AB Ab aB ab

    ab AaBb Aabb aaBb aabb

    ab AaBb Aabb aaBb aabb

    ab AaBb Aabb aaBb aabb

    ab AaBb Aabb aaBb aabb

    So we have four diffeerent genes:

    AaBb

    Aabb

    aaBb

    aabb

    Since A converts red to blue and B converts blue to green, then AaBb = Green (since they are heterozygous for both traits)

    Aabb = Blue (since A have the tendency of converting red to blue but b do not have the tendency to convert blue to green since it is recessive)

    aaBb = Red (since A is not present in the first place to convert red to blue, so the gene remains red)

    aabb = Red (since A is not present in the first place to convert red to blue, so the gene remains red)



    4:4:8 (blue:red:green)

    1:1:2 (blue:red:green)

    So since the question asked for only the proportion of red to green alone; we have 1:2 (red: green)
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