A student needs to prepare 250 mL of a 0.550 M aqueous solution of sucrose, C 12 H 22 O 11 (aq), which is used frequently in biological experiments?

Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.

Explanation:

You need to prepare 250. mL of a 0.550 M aqueous solution of sucrose, C12H22O11 (aq),

which is used frequently in biological experiments.

Based on your answer above, what is the value of x?

Solution:

A 0.550 M aqueous solution contains 0.550 mole of sucrose per liter of solution.

250 ml = 0.250 liter

Thus a 0.250 liter of a 0.550 M aqueous solution of sucrose contains 0.250 * 0.550 = 0.1375 mole of sucrose

Recall:

Mass = number of moles * mass of 1 mole

mass of 1 mole of C12H22O11

= 12 (12) + 1 (22) + 16 (11)

= 144 + 22 + 176

= 342 grams

Mass = 0.1375 * 342 = 47.025 grams of sucrose.

Dissolve 47.025 grams of sucrose in enough water to produce 250 ml of solution.