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4 September, 01:50

Freckles is dominant over no freckles. what percentage of offspring would be predicted to have freckles if the father was heterozygous for freckles and the mother did not have freckles

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  1. 4 September, 01:54
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    The answer would be 50%.

    Let's make a Punnett square for this:

    Let F - Freckles

    f - no freckles

    Father: Ff

    Mother: ff (She has no freckles, meaning she does not have the dominant allele)

    F f

    f Ff ff

    f Ff ff

    The count would then be 2/4 with freckles and 2/4 without freckles. So the percentage of would be 50% with freckles and 50% without freckles.
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