if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of banormal gametes (for the chromosomes involved in the nondisjunction) ?

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Niki

Biology

28 May, 06:34

if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of banormal gametes (for the chromosomes involved in the nondisjunction) ?

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Sophia Estes · Answer 1

Correct question:

if a nondisjunction occurs at anaphase I of the first meiotic division, what will the proportion of abnormal gametes (for the chromosomes involved in the nondisjunction) ?

Answer:

100%

Explanation:

Nondisjunction at meiosis-I means that two homologous chromosomes of at least one homologous pair fail to separate from each other during anaphase-I. This would result in the formation of one cell with one extra chromosome and the other with one less chromosome by the end of meiosis-I. Meiosis-II in these two cells would maintain this chromosome number in the daughter cells. Therefore, out of the total four gametes formed by the end of the meiosis, two would have one extra chromosome and would be denoted as "n+1". The rest of the two gametes would have one less chromosome and would be denoted as "n-1".