In humans, male-pattern baldness may be assumed to be controlled by an autosomal gene that occurs in two allelic forms. Allele B determines nonbaldness, and allele b determines pattern baldness. In males, because of the presence of testosterone, allele b is dominant over B. If a man and woman both with genotype Bb have a son, what is the chance that he will eventually be bald?

Question

Emmanuel Boyd

Biology

7 July, 03:07

In humans, male-pattern baldness may be assumed to be controlled by an autosomal gene that occurs in two allelic forms. Allele B determines nonbaldness, and allele b determines pattern baldness. In males, because of the presence of testosterone, allele b is dominant over B. If a man and woman both with genotype Bb have a son, what is the chance that he will eventually be bald?

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Adison West · Answer 1

75% of chance that their son would be bold

Explanation:

Doing a Punnet square, you can determine the chances that have the F1 whit certain characteristics.

In a Punnet square, the capital letter represents a dominant characteristic, and the lower case letter represents a recessive characteristic. But in this case, because of the presence of testosterone, allele b is dominant over B. Dominant mens that if is a pair of heterozygous chromosom, the dominant will appear in the phenotype, means physically. The recessive characteristic will prevail but only in the genotype