in Labrador retriever dogs, the dominant gene B determines black coat color and bb prouces brown. A separate gene E, however, shows dominant epistasis over the B and b alleles, resulting in a golden coat color. The recessive e allows expression of B and b. A breeder wants to know the genotypes of her three dogs, so she breeds them and makes note of the offspring of several litters. Determine the genotypes of the three dogs. a. golden female (dog 1) x golden male (dog 2) offspring: 7 golden, 1 black, 1 brown b. black female (dog 3) x golden male (dog 2) offspring: 8 golden, 5 black, 2 brown

Question

Bryson Day

Biology

13 April, 04:34

in Labrador retriever dogs, the dominant gene B determines black coat color and bb prouces brown. A separate gene E, however, shows dominant epistasis over the B and b alleles, resulting in a golden coat color. The recessive e allows expression of B and b. A breeder wants to know the genotypes of her three dogs, so she breeds them and makes note of the offspring of several litters. Determine the genotypes of the three dogs. a. golden female (dog 1) x golden male (dog 2) offspring: 7 golden, 1 black, 1 brown b. black female (dog 3) x golden male (dog 2) offspring: 8 golden, 5 black, 2 brown

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Answers (1)

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Trace · Answer 1

Dog 1: Eebb

Dog 2: EeBb

Dog 3: eeBb

Explanation:

Let's first analyze the offspring to know their genes

Black: ee (to be able to be black) Bb (because they told you black is dominant

Brown: ee (to be able to be brown) bb) (because is recessive)

Golden: Ee (because E is dominant to Golden) and here could be bb or Bb.

Now, we know what we are looking for: ee, Ee, Bb, and bb. Let's analyze the parents.

DOG 1: golden female

Ee and could be Bb or bb

DOG 2: golden male

Ee and could be Bb or bb

The had both color breed, so one will be bb and the other will be Bb.

DOG 3: black female

ee Bb (to be back)

So, because DOG 3 x DOG 2 had browned, we could say DOG 2 final alleles are EeBb and DOG 1 final alleles are Eebb