Kanye, Taylor's lab partner decided to perform a standard plate count from a sample of E. coli. Understanding that the plates should have 30 - 300 colonies, Kanye decide to aim for exactly 100 colonies.

If the original sample contained 1 x 10^8 CFU/ml, what is the total dilution that would yield 100 colonies?

Question

Nathen Powell

Biology

29 May, 13:36

Kanye, Taylor's lab partner decided to perform a standard plate count from a sample of E. coli. Understanding that the plates should have 30 - 300 colonies, Kanye decide to aim for exactly 100 colonies.

If the original sample contained 1 x 10^8 CFU/ml, what is the total dilution that would yield 100 colonies?

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Answers (1)

Know the Answer?

Teagan Buck · Answer 1

Total dilution is 10^5 that would yield 100 colonies.

Explanation:

1 x 10^8 cfu/mL * 1/x = 100 colonies

x = 10^6 cfu/ml

So,

1*106cfu/ml * 0.1 ml plated

=10^5