Ask Question
20 January, 05:55

The use of arsenate instead of phosphate by glyceraldehyde 3‑phosphate dehydrogenase produces 1‑arseno‑3‑phosphoglycerate. Assume that the presence of arsenate only affects the glycolysis step catalyzed by glyceraldehyde 3‑phosphate dehydrogenase and that 1‑arseno‑3‑phosphoglycerate spontaneously hydrolyzes to form 3‑phosphoglycerate.

How many ATP molecules would a single round of glycolysis consume and produce in this scenario?

+5
Answers (1)
  1. 20 January, 05:56
    0
    ATP consumed = 2 molecules

    ATP produced = 2 molecules.

    Explanation:

    Arsenate does not produce 1,3-bisphosphoglycerate, so it can be deduced that at least two ATP molecules are produced through normal glycolysis, remembering that phosphoglycerate kinase allows the reaction between 1,3-bisphosphoglycerate transforming it into 3 - phosphoglycerate and generating two ATP, phosphoglycerate kinase catalyzes this reaction and gives 2 ATP.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “The use of arsenate instead of phosphate by glyceraldehyde 3‑phosphate dehydrogenase produces 1‑arseno‑3‑phosphoglycerate. Assume that the ...” in 📗 Biology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers