Suppose you were instructed to add 0.2 mL of sample to 9.8 mL of diluent, but instead added 2.0 mL of sample. What was the intended dilution, and what was the actual dilution?

Question

Kenny Mathews

Biology

21 September, 03:01

Suppose you were instructed to add 0.2 mL of sample to 9.8 mL of diluent, but instead added 2.0 mL of sample. What was the intended dilution, and what was the actual dilution?

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Answers (2)

Know the Answer?

Camron Montgomery · Answer 1

Intended dilution = 50 x; Actual dilution = 5.9 x

Explanation:

Dilution factor = (Sample Volume + Diluent Volume) / Sample Volume

Intended dilution factor = (0.2 + 9.8) / 0.2

= 50

Actual dilution factor = (2 + 9.8) / 2

= 5.9

Nataly Christensen · Answer 2

Intended dilution: 50 times

Actual dilution: 5.9 times

Explanation:

Dilution: To decrease the concentration of the solute in a particular solution

Dilution = total volume of solution/volume of sample

Here, actual sample: 0.2ml, diluent: 2 ml

So, intended dilution = 10/0.2 = 50 times

Actual sample: 2 ml

So, actual dilution=11.8/2 = 5.9 times