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BiologyBiology
7 September, 03:31

Based on the pedigree chart, what is the probability that person A will birth an affected child if she mates with an unaffected wild type male?

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  1. 7 September, 03:50
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    25%

    Explanation:

    Una persona de fenotipo sano A puede presentar dos genotipos diferentes para la enfermedad en cuestión Aa o AA.

    Un macho de fenotipo sano puede presentar los mismos genotipos que la hembra.

    Suponiendo que la hembra y el macho presentan genotipo Aa podemos obtener para cada uno dos gametas diferentes A y a. Cruzamos las gametas y obtenemos:

    A a

    A AA Aa

    a Aa aa

    only genotype aa presents the disease phenotype
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