if a man is homozygous dominant for bent fifth finger and a woman is homozygous recessive. What is the probability that any offspring will have a bent fifth finger?

100 %

All the offsprings will have bent fifth finger if dominant trait is expressed

Explanation:

Let "F" represents the dominant bent fifth finger trait while

"f" represents the recessive trait.

Now, the genotype of parents is as follows -

a) Man with homozygous dominant bent fifth finger "FF"

b) Woman with homozygous recessive trait "ff"

When a cross is carried out between these two parents, the following offsprings will result -

FF x ff

Ff, Ff, Ff, Ff

All the offsprings are heterpzygous with two paired allele of which one is dominant and the other is recessive.

Thus, all the offsprings will have bent fifth finger if dominant trait is expressed.