The information in the table shows the possible genotypes resulting from the mating of two heterozygotes aadd. the allele a codes for normal pigmentation, a for albinism, d for dimpled chin, and d for non-dimpled chin. what fraction of offspring would be expected to be albino with a non-dimpled chin?

a. 1/2

b. 1/4

c. 3/4

d. 2/8

e. 1/16

Question

Cesar Sanford

Biology

2 June, 15:01

The information in the table shows the possible genotypes resulting from the mating of two heterozygotes aadd. the allele a codes for normal pigmentation, a for albinism, d for dimpled chin, and d for non-dimpled chin. what fraction of offspring would be expected to be albino with a non-dimpled chin?

a. 1/2

b. 1/4

c. 3/4

d. 2/8

e. 1/16

+4

Answers (1)

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Yusuf Ritter · Answer 1

Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.

When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.