A mutation creates a dominant negative allele of a particular gene. The gene encodes a protein that forms a trimer within the cell. If one or more of the subunits has the mutant structure, the entire trimeric protein is inactive. In a heterozygous cell, if the proteins of both alleles are present at the same levels, what percent of the trimers present in the cell will be active?

a. 100%

b. 87.5%

c. 50%

d. 33%

e. 12.5%

Question

Ishaan Barr

Biology

19 July, 14:39

A mutation creates a dominant negative allele of a particular gene. The gene encodes a protein that forms a trimer within the cell. If one or more of the subunits has the mutant structure, the entire trimeric protein is inactive. In a heterozygous cell, if the proteins of both alleles are present at the same levels, what percent of the trimers present in the cell will be active?

a. 100%

b. 87.5%

c. 50%

d. 33%

e. 12.5%

+3

Answers (2)

Know the Answer?

Cale Fitzpatrick · Answer 1

e. 12.5%

Explanation:

There are 12.5 % percent of the trimers present in the cell will be inactive for a heterozygous individual, If atleast one of the subunits has mutant gene.

Charles Schmitt · Answer 2

Charles Schmitt 19 July, 15:08

0

The correct answer is 12.5%