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17 February, 13:58

Two genes are 22 map units apart on the same chromosome. A true-breeding GGhh individual is crossed to a true-breeding ggHH individual. The F1 offspring are mated to gghh individuals. If this testcross produces 1000 offspring, how many of them would you expect to be GgHh?

Select one:

a. 390

b. 250

c. 220

d. 110

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Answers (1)
  1. 17 February, 14:13
    0
    d. 110

    Explanation:

    Parental cross: Gh/Gh x gH/gH

    F1: Gh/gH

    The following test cross experiment is done:

    Gh/gH x gh/gh

    Gametes produced by these individuals:

    - gh/gh: gh (probability of 1)

    - Gh/gH:

    Gh (parental) gH (parental) GH (recombinant) gh (recombinant)

    The formula that relates genetic distance with recombination frequency is:

    Genetic Distance (m. u.) = Recombination Frequency X 100

    In this problem:

    22 m. u. / 100 = Recombination Frequency

    0.22 = Recombination Frequency

    The recombination frequency altogether is 0.22, but there are 2 possible types of recombinant gametes and when one is generated, the other one is generated as well. Therefore, each recombinant gamete has a frequency of half the total recombination frequency: 0.11

    In an offspring of 1000 individuals, I would expect 110 to be GH/gh.
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