Which of the following is true? Group of answer choices When glucose is present, cAMP levels are high, so CAP is active and can bind to the activator When glucose is absent, cAMP levels are high, so CAP is active and can bind to the activator When glucose is present, cAMP levels are low, so CAP is active and cannot bind to the activator When glucose is absent, cAMP levels are high, so CAP is inactive and cannot bind to the activator

the correct answer is "when glucose is present, cAMP levels are high, so CAp is active and can bind to the activator"

Explanation:

CAMP is synthesized from ATP by the enzyme adenylate cyclase which is located in the cell membrane. This enzyme is activated by Gα or Gα-activator subunit activators, belonging to protein G, and inhibited by agonists of adenylate cyclase G or Gi inhibitors, both coupled protein receptors. Hepatic adenylate cyclase responds more strongly to glucagon, whereas muscle adenylate responds more strongly to adrenaline.

The breakdown of cAMP to 5'-AMP is catalyzed by the enzyme phosphodiesterase.

that is why the cyclic amp is only present with an increase in ATP (adenosistriphosphate) and therefore with the presence of glucose in the blood (considering that the person does not present insulin disorders with respect to the assimilation of glucose)

Answer

Glucose is absent, cAMP levels are high, CAP is inactive and cannot bind to the activator

Explanation:

The lac operon can only be transcribed in the absence of glucose. cAMP can only bind to CAP in the absence of glucose making it possible for CAP to bind to DNA.