In pea plants, the allele for tall stalks (T) is dominant over the allele for short stalks (t). Suppose a cross between a tall pea plant and a short pea plant produces 43 tall offspring and 47 short offspring. If one of the tall offspring is crossed with one of the short offspring, what ratio of genotypes would be most likely in their offspring

Tt - 1/2

tt - 1/2

Explanation:

A cross between a tall pea plant and a short pea plant that produces 43 tall and 47 short offpsring (almost 1:1) is most likely a cross involving a heterozygous tall individual and a homozygous short individual.

Tt x tt

Offspring = Tt Tt tt tt (50% tall and 50% short)

If one of the tall offspring (Tt) is crossed with one of the short offspring (tt):

Tt x tt

Offspring = Tt Tt tt tt

Genotype ratio = 2Tt:2tt

Hence,

Tt = 1/2

tt = 1/2

the ratio will be in equal proportion of 1:1

Explanation:

assuming that dominant TT is crossed below with recessive short stalk (tt).

the F1 is Tt, Tt, Tt, Tt.

if one of the heterozygote dominant (Tt) is crossed with the (homozygote recessive) tt.

Then in F2

Tt, Tt = 2; tt, tt,=2

2:2 is formed, which equals 1 (Tt) : 1 (tt) when cut through to simplest whole number.