g Assume that for a given gene a mutation creates an allele that functions as a dominant negative. The gene codes for a protein that forms a tetramer (4) within the cell. If at least one of the subunits has the mutant structure the entire protein is inactivated. For a heterozygous individual, what percent of the tretramers present in the cell will be inactive?

Question

Gavin Valencia

Biology

29 January, 14:35

g Assume that for a given gene a mutation creates an allele that functions as a dominant negative. The gene codes for a protein that forms a tetramer (4) within the cell. If at least one of the subunits has the mutant structure the entire protein is inactivated. For a heterozygous individual, what percent of the tretramers present in the cell will be inactive?

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Ray Fitzgerald · Answer 1

At least 50% of the tetramers will be inactive for this individual

Explanation:

A protein resulting from a mutation that is dominant negative will have an detrimental impact on the wild-type protein as well. Especially if the mutated protein can interact with the same substances as the normal, wild-type protein.

For an individual who is heterozygous, there will be one wild-type copy and one mutant copy of the allele present. For each copy, a protein will be expressed and the tetramers from the mutant copy will be defective - so 50% of the protein tetramers will be inactive at least.

Hope that answers the question, have a great day!